3(2d+4)=6-2(d-3)+8d

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Solution for 3(2d+4)=6-2(d-3)+8d equation:


Simplifying
3(2d + 4) = 6 + -2(d + -3) + 8d

Reorder the terms:
3(4 + 2d) = 6 + -2(d + -3) + 8d
(4 * 3 + 2d * 3) = 6 + -2(d + -3) + 8d
(12 + 6d) = 6 + -2(d + -3) + 8d

Reorder the terms:
12 + 6d = 6 + -2(-3 + d) + 8d
12 + 6d = 6 + (-3 * -2 + d * -2) + 8d
12 + 6d = 6 + (6 + -2d) + 8d

Combine like terms: 6 + 6 = 12
12 + 6d = 12 + -2d + 8d

Combine like terms: -2d + 8d = 6d
12 + 6d = 12 + 6d

Add '-12' to each side of the equation.
12 + -12 + 6d = 12 + -12 + 6d

Combine like terms: 12 + -12 = 0
0 + 6d = 12 + -12 + 6d
6d = 12 + -12 + 6d

Combine like terms: 12 + -12 = 0
6d = 0 + 6d
6d = 6d

Add '-6d' to each side of the equation.
6d + -6d = 6d + -6d

Combine like terms: 6d + -6d = 0
0 = 6d + -6d

Combine like terms: 6d + -6d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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