3(2d+4)=2(d-6)+6

Solution for 3(2d+4)=2(d-6)+6 equation:

3(2d+4)=2(d-6)+6

We move all terms to the left:

3(2d+4)-(2(d-6)+6)=0

We multiply parentheses

6d-(2(d-6)+6)+12=0


We calculate terms in parentheses: -(2(d-6)+6), so:

2(d-6)+6

We multiply parentheses

2d-12+6

We add all the numbers together, and all the variables

2d-6

Back to the equation:

-(2d-6)


We get rid of parentheses

6d-2d+6+12=0

We add all the numbers together, and all the variables

4d+18=0

We move all terms containing d to the left, all other terms to the right

4d=-18

d=-18/4

d=-4+1/2