3(2d+3)=5-4(3-d)

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Solution for 3(2d+3)=5-4(3-d) equation: 



3(2d+3)=5-4(3-d)

We move all terms to the left:

3(2d+3)-(5-4(3-d))=0

We add all the numbers together, and all the variables

3(2d+3)-(5-4(-1d+3))=0

We multiply parentheses

6d-(5-4(-1d+3))+9=0



We calculate terms in parentheses: -(5-4(-1d+3)), so:

5-4(-1d+3)

determiningTheFunctionDomain
-4(-1d+3)+5

We multiply parentheses

4d-12+5

We add all the numbers together, and all the variables

4d-7

Back to the equation:

-(4d-7)



We get rid of parentheses

6d-4d+7+9=0

We add all the numbers together, and all the variables

2d+16=0

We move all terms containing d to the left, all other terms to the right

2d=-16

d=-16/2

d=-8

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