3(2c-5)=10c-7

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Solution for 3(2c-5)=10c-7 equation: 



3(2c-5)=10c-7

We move all terms to the left:

3(2c-5)-(10c-7)=0

We multiply parentheses

6c-(10c-7)-15=0

We get rid of parentheses

6c-10c+7-15=0

We add all the numbers together, and all the variables

-4c-8=0

We move all terms containing c to the left, all other terms to the right

-4c=8

c=8/-4

c=-2

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