3(2c-4)-2(c-8)=-28

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Solution for 3(2c-4)-2(c-8)=-28 equation: 


Simplifying
3(2c + -4) + -2(c + -8) = -28

Reorder the terms:
3(-4 + 2c) + -2(c + -8) = -28
(-4 * 3 + 2c * 3) + -2(c + -8) = -28
(-12 + 6c) + -2(c + -8) = -28

Reorder the terms:
-12 + 6c + -2(-8 + c) = -28
-12 + 6c + (-8 * -2 + c * -2) = -28
-12 + 6c + (16 + -2c) = -28

Reorder the terms:
-12 + 16 + 6c + -2c = -28

Combine like terms: -12 + 16 = 4
4 + 6c + -2c = -28

Combine like terms: 6c + -2c = 4c
4 + 4c = -28

Solving
4 + 4c = -28

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 4c = -28 + -4

Combine like terms: 4 + -4 = 0
0 + 4c = -28 + -4
4c = -28 + -4

Combine like terms: -28 + -4 = -32
4c = -32

Divide each side by '4'.
c = -8

Simplifying
c = -8

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