3(2c-3)=5(7c+14)

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Solution for 3(2c-3)=5(7c+14) equation: 



3(2c-3)=5(7c+14)

We move all terms to the left:

3(2c-3)-(5(7c+14))=0

We multiply parentheses

6c-(5(7c+14))-9=0



We calculate terms in parentheses: -(5(7c+14)), so:

5(7c+14)

We multiply parentheses

35c+70

Back to the equation:

-(35c+70)



We get rid of parentheses

6c-35c-70-9=0

We add all the numbers together, and all the variables

-29c-79=0

We move all terms containing c to the left, all other terms to the right

-29c=79

c=79/-29

c=-2+21/29

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