3(2c-1)+7=6c-3-2(2-4c)

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Solution for 3(2c-1)+7=6c-3-2(2-4c) equation: 



3(2c-1)+7=6c-3-2(2-4c)

We move all terms to the left:

3(2c-1)+7-(6c-3-2(2-4c))=0

We add all the numbers together, and all the variables

3(2c-1)-(6c-3-2(-4c+2))+7=0

We multiply parentheses

6c-(6c-3-2(-4c+2))-3+7=0



We calculate terms in parentheses: -(6c-3-2(-4c+2)), so:

6c-3-2(-4c+2)

determiningTheFunctionDomain
6c-2(-4c+2)-3

We multiply parentheses

6c+8c-4-3

We add all the numbers together, and all the variables

14c-7

Back to the equation:

-(14c-7)



We add all the numbers together, and all the variables

6c-(14c-7)+4=0

We get rid of parentheses

6c-14c+7+4=0

We add all the numbers together, and all the variables

-8c+11=0

We move all terms containing c to the left, all other terms to the right

-8c=-11

c=-11/-8

c=1+3/8

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