3(2c+d)-2(c+d)=0

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Solution for 3(2c+d)-2(c+d)=0 equation:


Simplifying
3(2c + d) + -2(c + d) = 0
(2c * 3 + d * 3) + -2(c + d) = 0
(6c + 3d) + -2(c + d) = 0
6c + 3d + (c * -2 + d * -2) = 0
6c + 3d + (-2c + -2d) = 0

Reorder the terms:
6c + -2c + 3d + -2d = 0

Combine like terms: 6c + -2c = 4c
4c + 3d + -2d = 0

Combine like terms: 3d + -2d = 1d
4c + 1d = 0

Solving
4c + 1d = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1d' to each side of the equation.
4c + 1d + -1d = 0 + -1d

Combine like terms: 1d + -1d = 0
4c + 0 = 0 + -1d
4c = 0 + -1d
Remove the zero:
4c = -1d

Divide each side by '4'.
c = -0.25d

Simplifying
c = -0.25d

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