3(2c+7)=4c+49

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Solution for 3(2c+7)=4c+49 equation: 



3(2c+7)=4c+49

We move all terms to the left:

3(2c+7)-(4c+49)=0

We multiply parentheses

6c-(4c+49)+21=0

We get rid of parentheses

6c-4c-49+21=0

We add all the numbers together, and all the variables

2c-28=0

We move all terms containing c to the left, all other terms to the right

2c=28

c=28/2

c=14

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