3(2c+7)-3c=4(c+5)

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Solution for 3(2c+7)-3c=4(c+5) equation: 



3(2c+7)-3c=4(c+5)

We move all terms to the left:

3(2c+7)-3c-(4(c+5))=0

We add all the numbers together, and all the variables

-3c+3(2c+7)-(4(c+5))=0

We multiply parentheses

-3c+6c-(4(c+5))+21=0



We calculate terms in parentheses: -(4(c+5)), so:

4(c+5)

We multiply parentheses

4c+20

Back to the equation:

-(4c+20)



We add all the numbers together, and all the variables

3c-(4c+20)+21=0

We get rid of parentheses

3c-4c-20+21=0

We add all the numbers together, and all the variables

-1c+1=0

We move all terms containing c to the left, all other terms to the right

-c=-1

c=-1/-1

c=1

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