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3(2c+7)+c=7(c+5)
We move all terms to the left:
3(2c+7)+c-(7(c+5))=0
We add all the numbers together, and all the variables
c+3(2c+7)-(7(c+5))=0
We multiply parentheses
c+6c-(7(c+5))+21=0
We calculate terms in parentheses: -(7(c+5)), so:We add all the numbers together, and all the variables
7(c+5)
We multiply parentheses
7c+35
Back to the equation:
-(7c+35)
7c-(7c+35)+21=0
We get rid of parentheses
7c-7c-35+21=0
We add all the numbers together, and all the variables
-14!=0
There is no solution for this equation
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