3(2c+5)=4(c-3)

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Solution for 3(2c+5)=4(c-3) equation:


Simplifying
3(2c + 5) = 4(c + -3)

Reorder the terms:
3(5 + 2c) = 4(c + -3)
(5 * 3 + 2c * 3) = 4(c + -3)
(15 + 6c) = 4(c + -3)

Reorder the terms:
15 + 6c = 4(-3 + c)
15 + 6c = (-3 * 4 + c * 4)
15 + 6c = (-12 + 4c)

Solving
15 + 6c = -12 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
15 + 6c + -4c = -12 + 4c + -4c

Combine like terms: 6c + -4c = 2c
15 + 2c = -12 + 4c + -4c

Combine like terms: 4c + -4c = 0
15 + 2c = -12 + 0
15 + 2c = -12

Add '-15' to each side of the equation.
15 + -15 + 2c = -12 + -15

Combine like terms: 15 + -15 = 0
0 + 2c = -12 + -15
2c = -12 + -15

Combine like terms: -12 + -15 = -27
2c = -27

Divide each side by '2'.
c = -13.5

Simplifying
c = -13.5

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