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3(2c+5)=12(3c+4)
We move all terms to the left:
3(2c+5)-(12(3c+4))=0
We multiply parentheses
6c-(12(3c+4))+15=0
We calculate terms in parentheses: -(12(3c+4)), so:We get rid of parentheses
12(3c+4)
We multiply parentheses
36c+48
Back to the equation:
-(36c+48)
6c-36c-48+15=0
We add all the numbers together, and all the variables
-30c-33=0
We move all terms containing c to the left, all other terms to the right
-30c=33
c=33/-30
c=-1+1/10
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