3(2c+4)=2c+24

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Solution for 3(2c+4)=2c+24 equation: 



3(2c+4)=2c+24

We move all terms to the left:

3(2c+4)-(2c+24)=0

We multiply parentheses

6c-(2c+24)+12=0

We get rid of parentheses

6c-2c-24+12=0

We add all the numbers together, and all the variables

4c-12=0

We move all terms containing c to the left, all other terms to the right

4c=12

c=12/4

c=3

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