3(2c+2)=2(3c-2)

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Solution for 3(2c+2)=2(3c-2) equation: 



3(2c+2)=2(3c-2)

We move all terms to the left:

3(2c+2)-(2(3c-2))=0

We multiply parentheses

6c-(2(3c-2))+6=0



We calculate terms in parentheses: -(2(3c-2)), so:

2(3c-2)

We multiply parentheses

6c-4

Back to the equation:

-(6c-4)



We get rid of parentheses

6c-6c+4+6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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