3(2b-1)-7=6(b-10)

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Solution for 3(2b-1)-7=6(b-10) equation: 



3(2b-1)-7=6(b-10)

We move all terms to the left:

3(2b-1)-7-(6(b-10))=0

We multiply parentheses

6b-(6(b-10))-3-7=0



We calculate terms in parentheses: -(6(b-10)), so:

6(b-10)

We multiply parentheses

6b-60

Back to the equation:

-(6b-60)



We add all the numbers together, and all the variables

6b-(6b-60)-10=0

We get rid of parentheses

6b-6b+60-10=0

We add all the numbers together, and all the variables

50!=0

There is no solution for this equation

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