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3(2a-4)=4(a+5)
We move all terms to the left:
3(2a-4)-(4(a+5))=0
We multiply parentheses
6a-(4(a+5))-12=0
We calculate terms in parentheses: -(4(a+5)), so:We get rid of parentheses
4(a+5)
We multiply parentheses
4a+20
Back to the equation:
-(4a+20)
6a-4a-20-12=0
We add all the numbers together, and all the variables
2a-32=0
We move all terms containing a to the left, all other terms to the right
2a=32
a=32/2
a=16
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