3(2a+5)+4(3a-1)=109

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Solution for 3(2a+5)+4(3a-1)=109 equation: 



3(2a+5)+4(3a-1)=109

We move all terms to the left:

3(2a+5)+4(3a-1)-(109)=0

We multiply parentheses

6a+12a+15-4-109=0

We add all the numbers together, and all the variables

18a-98=0

We move all terms containing a to the left, all other terms to the right

18a=98

a=98/18

a=5+4/9

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