3(27+3)=9y-15

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Solution for 3(27+3)=9y-15 equation:



3(27+3)=9y-15
We move all terms to the left:
3(27+3)-(9y-15)=0
We add all the numbers together, and all the variables
-(9y-15)+330=0
We get rid of parentheses
-9y+15+330=0
We add all the numbers together, and all the variables
-9y+345=0
We move all terms containing y to the left, all other terms to the right
-9y=-345
y=-345/-9
y=38+1/3

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