3(24x-54)=11(x-4)+5

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Solution for 3(24x-54)=11(x-4)+5 equation: 



3(24x-54)=11(x-4)+5

We move all terms to the left:

3(24x-54)-(11(x-4)+5)=0

We multiply parentheses

72x-(11(x-4)+5)-162=0



We calculate terms in parentheses: -(11(x-4)+5), so:

11(x-4)+5

We multiply parentheses

11x-44+5

We add all the numbers together, and all the variables

11x-39

Back to the equation:

-(11x-39)



We get rid of parentheses

72x-11x+39-162=0

We add all the numbers together, and all the variables

61x-123=0

We move all terms containing x to the left, all other terms to the right

61x=123

x=123/61

x=2+1/61

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