3(23-z)=25

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Solution for 3(23-z)=25 equation: 



3(23-z)=25

We move all terms to the left:

3(23-z)-(25)=0

We add all the numbers together, and all the variables

3(-1z+23)-25=0

We multiply parentheses

-3z+69-25=0

We add all the numbers together, and all the variables

-3z+44=0

We move all terms containing z to the left, all other terms to the right

-3z=-44

z=-44/-3

z=14+2/3

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