3(23+2b)+4b=48

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Solution for 3(23+2b)+4b=48 equation:


3(23+2b)+4b=48

We simplify the equation to the form, which is simple to understand 
3(23+2b)+4b=48

Reorder the terms in parentheses
+(+69+6b)+4b=48

Remove unnecessary parentheses
+69+6b+4b=+48

We move all terms containing b to the left and all other terms to the right. 
+6b+4b=+48-69

We simplify left and right side of the equation. 
+10b=-21

We divide both sides of the equation by 10 to get b. 
b=-2.1

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