3(20-b)=35

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Solution for 3(20-b)=35 equation: 



3(20-b)=35

We move all terms to the left:

3(20-b)-(35)=0

We add all the numbers together, and all the variables

3(-1b+20)-35=0

We multiply parentheses

-3b+60-35=0

We add all the numbers together, and all the variables

-3b+25=0

We move all terms containing b to the left, all other terms to the right

-3b=-25

b=-25/-3

b=8+1/3

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