3(20-3x)=(x-12)

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Solution for 3(20-3x)=(x-12) equation: 



3(20-3x)=(x-12)

We move all terms to the left:

3(20-3x)-((x-12))=0

We add all the numbers together, and all the variables

3(-3x+20)-((x-12))=0

We multiply parentheses

-9x-((x-12))+60=0



We calculate terms in parentheses: -((x-12)), so:

(x-12)

We get rid of parentheses

x-12

Back to the equation:

-(x-12)



We get rid of parentheses

-9x-x+12+60=0

We add all the numbers together, and all the variables

-10x+72=0

We move all terms containing x to the left, all other terms to the right

-10x=-72

x=-72/-10

x=7+1/5

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