3(20+b)=228

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Solution for 3(20+b)=228 equation: 



3(20+b)=228

We move all terms to the left:

3(20+b)-(228)=0

We add all the numbers together, and all the variables

3(b+20)-228=0

We multiply parentheses

3b+60-228=0

We add all the numbers together, and all the variables

3b-168=0

We move all terms containing b to the left, all other terms to the right

3b=168

b=168/3

b=56

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