3(20)=60-4x+28

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Solution for 3(20)=60-4x+28 equation: 



3(20)=60-4x+28

We move all terms to the left:

3(20)-(60-4x+28)=0

We add all the numbers together, and all the variables

-(-4x+88)+320=0

We get rid of parentheses

4x-88+320=0

We add all the numbers together, and all the variables

4x+232=0

We move all terms containing x to the left, all other terms to the right

4x=-232

x=-232/4

x=-58

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