3(2-z)/5=z

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Solution for 3(2-z)/5=z equation: 


z in (-oo:+oo)

(3*(2-z))/5 = z // - z

(3*(2-z))/5-z = 0

(3*(2-z))/5+(5*(-z))/5 = 0

3*(2-z)+5*(-z) = 0

6-8*z = 0

(6-8*z)/5 = 0

(6-8*z)/5 = 0 // * 5

6-8*z = 0

6-8*z = 0 // - 6

-8*z = -6 // : -8

z = -6/(-8)

z = 3/4

z = 3/4

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