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3(2-x)=2(4-2x)
We move all terms to the left:
3(2-x)-(2(4-2x))=0
We add all the numbers together, and all the variables
3(-1x+2)-(2(-2x+4))=0
We multiply parentheses
-3x-(2(-2x+4))+6=0
We calculate terms in parentheses: -(2(-2x+4)), so:We get rid of parentheses
2(-2x+4)
We multiply parentheses
-4x+8
Back to the equation:
-(-4x+8)
-3x+4x-8+6=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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