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3(2-x)-5=2(1-x)-4
We move all terms to the left:
3(2-x)-5-(2(1-x)-4)=0
We add all the numbers together, and all the variables
3(-1x+2)-(2(-1x+1)-4)-5=0
We multiply parentheses
-3x-(2(-1x+1)-4)+6-5=0
We calculate terms in parentheses: -(2(-1x+1)-4), so:We add all the numbers together, and all the variables
2(-1x+1)-4
We multiply parentheses
-2x+2-4
We add all the numbers together, and all the variables
-2x-2
Back to the equation:
-(-2x-2)
-3x-(-2x-2)+1=0
We get rid of parentheses
-3x+2x+2+1=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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