3(2-x)+6=5(x-4)

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Solution for 3(2-x)+6=5(x-4) equation: 



3(2-x)+6=5(x-4)

We move all terms to the left:

3(2-x)+6-(5(x-4))=0

We add all the numbers together, and all the variables

3(-1x+2)-(5(x-4))+6=0

We multiply parentheses

-3x-(5(x-4))+6+6=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

-3x-(5x-20)+12=0

We get rid of parentheses

-3x-5x+20+12=0

We add all the numbers together, and all the variables

-8x+32=0

We move all terms containing x to the left, all other terms to the right

-8x=-32

x=-32/-8

x=+4

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