3(2-w)-w=6+2(w-1)

Solution for 3(2-w)-w=6+2(w-1) equation:

3(2-w)-w=6+2(w-1)

We move all terms to the left:

3(2-w)-w-(6+2(w-1))=0

We add all the numbers together, and all the variables

3(-1w+2)-w-(6+2(w-1))=0

We add all the numbers together, and all the variables

-1w+3(-1w+2)-(6+2(w-1))=0

We multiply parentheses

-1w-3w-(6+2(w-1))+6=0


We calculate terms in parentheses: -(6+2(w-1)), so:

6+2(w-1)

determiningTheFunctionDomain
2(w-1)+6

We multiply parentheses

2w-2+6

We add all the numbers together, and all the variables

2w+4

Back to the equation:

-(2w+4)


We add all the numbers together, and all the variables

-4w-(2w+4)+6=0

We get rid of parentheses

-4w-2w-4+6=0

We add all the numbers together, and all the variables

-6w+2=0

We move all terms containing w to the left, all other terms to the right

-6w=-2

w=-2/-6

w=1/3