3(2-6c)=-2(10c-5)

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Solution for 3(2-6c)=-2(10c-5) equation:



3(2-6c)=-2(10c-5)
We move all terms to the left:
3(2-6c)-(-2(10c-5))=0
We add all the numbers together, and all the variables
3(-6c+2)-(-2(10c-5))=0
We multiply parentheses
-18c-(-2(10c-5))+6=0
We calculate terms in parentheses: -(-2(10c-5)), so:
-2(10c-5)
We multiply parentheses
-20c+10
Back to the equation:
-(-20c+10)
We get rid of parentheses
-18c+20c-10+6=0
We add all the numbers together, and all the variables
2c-4=0
We move all terms containing c to the left, all other terms to the right
2c=4
c=4/2
c=2

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