3(2-4)=7z+4

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Solution for 3(2-4)=7z+4 equation: 



3(2-4)=7z+4

We move all terms to the left:

3(2-4)-(7z+4)=0

We add all the numbers together, and all the variables

-(7z+4)+3(-2)=0

We add all the numbers together, and all the variables

-(7z+4)-6=0

We get rid of parentheses

-7z-4-6=0

We add all the numbers together, and all the variables

-7z-10=0

We move all terms containing z to the left, all other terms to the right

-7z=10

z=10/-7

z=-1+3/7

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