3(2-3x)=-7-2(x-3)

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Solution for 3(2-3x)=-7-2(x-3) equation: 



3(2-3x)=-7-2(x-3)

We move all terms to the left:

3(2-3x)-(-7-2(x-3))=0

We add all the numbers together, and all the variables

3(-3x+2)-(-7-2(x-3))=0

We multiply parentheses

-9x-(-7-2(x-3))+6=0



We calculate terms in parentheses: -(-7-2(x-3)), so:

-7-2(x-3)

determiningTheFunctionDomain
-2(x-3)-7

We multiply parentheses

-2x+6-7

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We get rid of parentheses

-9x+2x+1+6=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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