3(2+x)=4-(x-2)=

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Solution for 3(2+x)=4-(x-2)= equation: 



3(2+x)=4-(x-2)=

We move all terms to the left:

3(2+x)-(4-(x-2))=0

We add all the numbers together, and all the variables

3(x+2)-(4-(x-2))=0

We multiply parentheses

3x-(4-(x-2))+6=0



We calculate terms in parentheses: -(4-(x-2)), so:

4-(x-2)

determiningTheFunctionDomain
-(x-2)+4

We get rid of parentheses

-x+2+4

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We get rid of parentheses

3x+1x-6+6=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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