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3(2+x)=3x+(2-x)
We move all terms to the left:
3(2+x)-(3x+(2-x))=0
We add all the numbers together, and all the variables
3(x+2)-(3x+(-1x+2))=0
We multiply parentheses
3x-(3x+(-1x+2))+6=0
We calculate terms in parentheses: -(3x+(-1x+2)), so:We get rid of parentheses
3x+(-1x+2)
We get rid of parentheses
3x-1x+2
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
3x-2x-2+6=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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