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3(2+x)=2(1+x)
We move all terms to the left:
3(2+x)-(2(1+x))=0
We add all the numbers together, and all the variables
3(x+2)-(2(x+1))=0
We multiply parentheses
3x-(2(x+1))+6=0
We calculate terms in parentheses: -(2(x+1)), so:We get rid of parentheses
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
3x-2x-2+6=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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