3(2+c)=2(c-5)

Solution for 3(2+c)=2(c-5) equation:

Simplifying
3(2 + c) = 2(c + -5)
(2 * 3 + c * 3) = 2(c + -5)
(6 + 3c) = 2(c + -5)

Reorder the terms:
6 + 3c = 2(-5 + c)
6 + 3c = (-5 * 2 + c * 2)
6 + 3c = (-10 + 2c)

Solving
6 + 3c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
6 + 3c + -2c = -10 + 2c + -2c

Combine like terms: 3c + -2c = 1c
6 + 1c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
6 + 1c = -10 + 0
6 + 1c = -10

Add '-6' to each side of the equation.
6 + -6 + 1c = -10 + -6

Combine like terms: 6 + -6 = 0
0 + 1c = -10 + -6
1c = -10 + -6

Combine like terms: -10 + -6 = -16
1c = -16

Divide each side by '1'.
c = -16

Simplifying
c = -16