3(2+c)=2(1+c)

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Solution for 3(2+c)=2(1+c) equation: 



3(2+c)=2(1+c)

We move all terms to the left:

3(2+c)-(2(1+c))=0

We add all the numbers together, and all the variables

3(c+2)-(2(c+1))=0

We multiply parentheses

3c-(2(c+1))+6=0



We calculate terms in parentheses: -(2(c+1)), so:

2(c+1)

We multiply parentheses

2c+2

Back to the equation:

-(2c+2)



We get rid of parentheses

3c-2c-2+6=0

We add all the numbers together, and all the variables

c+4=0

We move all terms containing c to the left, all other terms to the right

c=-4

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