3(2+c)=(c-5)

Solution for 3(2+c)=(c-5) equation:

Simplifying
3(2 + c) = (c + -5)
(2 * 3 + c * 3) = (c + -5)
(6 + 3c) = (c + -5)

Reorder the terms:
6 + 3c = (-5 + c)

Remove parenthesis around (-5 + c)
6 + 3c = -5 + c

Solving
6 + 3c = -5 + c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
6 + 3c + -1c = -5 + c + -1c

Combine like terms: 3c + -1c = 2c
6 + 2c = -5 + c + -1c

Combine like terms: c + -1c = 0
6 + 2c = -5 + 0
6 + 2c = -5

Add '-6' to each side of the equation.
6 + -6 + 2c = -5 + -6

Combine like terms: 6 + -6 = 0
0 + 2c = -5 + -6
2c = -5 + -6

Combine like terms: -5 + -6 = -11
2c = -11

Divide each side by '2'.
c = -5.5

Simplifying
c = -5.5