3(2+4m)=6(1+2m)

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Solution for 3(2+4m)=6(1+2m) equation: 



3(2+4m)=6(1+2m)

We move all terms to the left:

3(2+4m)-(6(1+2m))=0

We add all the numbers together, and all the variables

3(4m+2)-(6(2m+1))=0

We multiply parentheses

12m-(6(2m+1))+6=0



We calculate terms in parentheses: -(6(2m+1)), so:

6(2m+1)

We multiply parentheses

12m+6

Back to the equation:

-(12m+6)



We get rid of parentheses

12m-12m-6+6=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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