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3(2(x+1)-(x+2))=2x+1
We move all terms to the left:
3(2(x+1)-(x+2))-(2x+1)=0
We get rid of parentheses
3(2(x+1)-(x+2))-2x-1=0
We add all the numbers together, and all the variables
-2x+3(2(x+1)-(x+2))-1=0
We move all terms containing x to the left, all other terms to the right
-2x+3(2(x+1)-(x+2))=1
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