3(1b+5)=4(2b-5)

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Solution for 3(1b+5)=4(2b-5) equation: 



3(1b+5)=4(2b-5)

We move all terms to the left:

3(1b+5)-(4(2b-5))=0

We add all the numbers together, and all the variables

3(b+5)-(4(2b-5))=0

We multiply parentheses

3b-(4(2b-5))+15=0



We calculate terms in parentheses: -(4(2b-5)), so:

4(2b-5)

We multiply parentheses

8b-20

Back to the equation:

-(8b-20)



We get rid of parentheses

3b-8b+20+15=0

We add all the numbers together, and all the variables

-5b+35=0

We move all terms containing b to the left, all other terms to the right

-5b=-35

b=-35/-5

b=+7

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