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3(18s)(s=2)
We move all terms to the left:
3(18s)(s-(2))=0
We multiply parentheses
318s^2-636s=0
a = 318; b = -636; c = 0;
Δ = b2-4ac
Δ = -6362-4·318·0
Δ = 404496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{404496}=636$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-636)-636}{2*318}=\frac{0}{636} =0 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-636)+636}{2*318}=\frac{1272}{636} =2 $
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