3(12-k)=3(k+21)

Solution for 3(12-k)=3(k+21) equation:

3(12-k)=3(k+21)

We move all terms to the left:

3(12-k)-(3(k+21))=0

We add all the numbers together, and all the variables

3(-1k+12)-(3(k+21))=0

We multiply parentheses

-3k-(3(k+21))+36=0


We calculate terms in parentheses: -(3(k+21)), so:

3(k+21)

We multiply parentheses

3k+63

Back to the equation:

-(3k+63)


We get rid of parentheses

-3k-3k-63+36=0

We add all the numbers together, and all the variables

-6k-27=0

We move all terms containing k to the left, all other terms to the right

-6k=27

k=27/-6

k=-4+1/2