3(12+2k)=2(-k+2)

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Solution for 3(12+2k)=2(-k+2) equation: 



3(12+2k)=2(-k+2)

We move all terms to the left:

3(12+2k)-(2(-k+2))=0

We add all the numbers together, and all the variables

3(2k+12)-(2(-1k+2))=0

We multiply parentheses

6k-(2(-1k+2))+36=0



We calculate terms in parentheses: -(2(-1k+2)), so:

2(-1k+2)

We multiply parentheses

-2k+4

Back to the equation:

-(-2k+4)



We get rid of parentheses

6k+2k-4+36=0

We add all the numbers together, and all the variables

8k+32=0

We move all terms containing k to the left, all other terms to the right

8k=-32

k=-32/8

k=-4

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