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3(11x+4)+4=1+4(3x+2)
We move all terms to the left:
3(11x+4)+4-(1+4(3x+2))=0
We multiply parentheses
33x-(1+4(3x+2))+12+4=0
We calculate terms in parentheses: -(1+4(3x+2)), so:We add all the numbers together, and all the variables
1+4(3x+2)
determiningTheFunctionDomain 4(3x+2)+1
We multiply parentheses
12x+8+1
We add all the numbers together, and all the variables
12x+9
Back to the equation:
-(12x+9)
33x-(12x+9)+16=0
We get rid of parentheses
33x-12x-9+16=0
We add all the numbers together, and all the variables
21x+7=0
We move all terms containing x to the left, all other terms to the right
21x=-7
x=-7/21
x=-1/3
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