3(11-c)=19+c

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Solution for 3(11-c)=19+c equation: 



3(11-c)=19+c

We move all terms to the left:

3(11-c)-(19+c)=0

We add all the numbers together, and all the variables

3(-1c+11)-(c+19)=0

We multiply parentheses

-3c-(c+19)+33=0

We get rid of parentheses

-3c-c-19+33=0

We add all the numbers together, and all the variables

-4c+14=0

We move all terms containing c to the left, all other terms to the right

-4c=-14

c=-14/-4

c=3+1/2

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