3(10x-4)=6(-8-x)

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Solution for 3(10x-4)=6(-8-x) equation: 



3(10x-4)=6(-8-x)

We move all terms to the left:

3(10x-4)-(6(-8-x))=0

We add all the numbers together, and all the variables

3(10x-4)-(6(-1x-8))=0

We multiply parentheses

30x-(6(-1x-8))-12=0



We calculate terms in parentheses: -(6(-1x-8)), so:

6(-1x-8)

We multiply parentheses

-6x-48

Back to the equation:

-(-6x-48)



We get rid of parentheses

30x+6x+48-12=0

We add all the numbers together, and all the variables

36x+36=0

We move all terms containing x to the left, all other terms to the right

36x=-36

x=-36/36

x=-1

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