3(10t-12)=2(-6+18t)

Solution for 3(10t-12)=2(-6+18t) equation:

3(10t-12)=2(-6+18t)

We move all terms to the left:

3(10t-12)-(2(-6+18t))=0

We add all the numbers together, and all the variables

3(10t-12)-(2(18t-6))=0

We multiply parentheses

30t-(2(18t-6))-36=0


We calculate terms in parentheses: -(2(18t-6)), so:

2(18t-6)

We multiply parentheses

36t-12

Back to the equation:

-(36t-12)


We get rid of parentheses

30t-36t+12-36=0

We add all the numbers together, and all the variables

-6t-24=0

We move all terms containing t to the left, all other terms to the right

-6t=24

t=24/-6

t=-4